Derivera $f(x)=x^{1/3}$
$f'(x)=1/3\dfrac{1}{x^{-2/3}}$
$f'(x)=1/3x^{4/3}$
$f'(x)=1/3\dfrac{1}{x^{2/3}}$
$f'(x)=1/3\dfrac{1}{x^{-1/3}}$
hints.expressions.help-title